This reads numbers from the standard input, and sorts them in increasing numerical order. It then prints the sorted numbers.
/* * LINKED LIST SORTER * * This program reads in numbers and sorts them in increasing numerical order * The data structure used is a linked list; each element looks like this: * +--------------+ * | data field | <--- holds the integer that you read in * +--------------+ * | next field | <--- holds pointer to next element in list * +--------------+ (NULL if nothing follows it) * * The pointer variable "head" contains a pointer to the first element in * the linked list (NULL if there are no elements in the linked list) */ #include <stdio.h> #include <stdlib.h> /* * structure for the list */ struct num { int data; /* data field (the number to be sorted) */ struct num *next; /* points to next element in linked list */ /* (NULL pointer if no next element) */ }; /* * pointer to the first element (the head) of the list * NULL if there's nothing in the list */ struct num *head = NULL; /* * create a new node * and initialize the two fields */ struct num *createnode(int n) { struct num *p; /* pointer to new space */ /* create the element, reporting errors */ if ((p = malloc(sizeof(struct num))) == NULL) return(NULL); /* initialize the element */ p->data = n; p->next = NULL; /* return a pointer to the new entity */ return(p); } /* * insert the element that new points to into the linked list, * and return a pointer to the (possibly new) head of the list */ struct num *insert(struct num *new) { struct num *prev, *temp; /* pointers used to insert new element */ /* empty list: put head at the front */ if (head == NULL) return(new); /* it goes before the first element */ if (head->data > new->data){ new->next = head; return(new); } /* * now walk the list * from here on in, prev->next == temp * we'll insert after prev and before temp */ prev = head; temp = head->next; while(temp != NULL && temp->data < new->data){ /* advance prev and temp */ prev = temp; temp = temp->next; } /* * here's the insertion * make prev->nect the new element * and new->next the one temp points to */ new->next = temp; prev->next = new; /* return the pointer to the head of the list */ return(head); } /* * the main routine * read in numbers and sort them */ int main(void) { int i; /* number of numbers read by scanf */ int n; /* what scanf read */ struct num *p; /* pointer to element for linked list */ /* * loop through the input */ while((i = scanf("%d", &n)) != EOF){ /* error check; was a number read? */ if (i == 0){ /* no; give error message and print rest of line */ fprintf(stderr, "illegal number: "); while((i = getchar()) != EOF && i != '\n') fputc(i, stderr); fputc('\n', stderr); continue; } /* create a new node, and print error message if failure */ if ((p = createnode(n)) == NULL){ fprintf(stderr, "no more memory on input %d\n", n); return(EXIT_FAILURE); } /* insert new element into linked list */ head = insert(p); } /* skip to next line, for cleaner output */ putchar('\n'); /* * print the list * start at the head, print the data field of each element * and go on to the next */ for(p = head; p != NULL; p = p->next) printf("%d\n", p->data); /* bye-bye */ return(EXIT_SUCCESS); }
ECS 30-A, Introduction to Programming Spring Quarter 2002 Email: [email protected] |